FAQ |
Calendar |
![]() |
|
Programming Share, tanya jawab, saling bantu antar programmer dengan berbagai macam bahasa pemrograman. |
![]() |
|
Thread Tools |
#1
|
|||
|
|||
![]()
langsung aj y gan,jd gni critanya..wktu ane lg bwt prgrm aritmatik encoding dgn coding ky gni: Spoiler for Coding form awal: Private Sub btnProcess_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnProcess.Click Dim i, k, n, d As Integer Dim s, a, b As String Dim huruf(1000) As String Dim index(1000) As Integer Dim var(5), prb(5) As Object n = 0 'Penginputan nilai variabel 'pemanggilan fungsi len() n = Len(txtInput.Text) If n = 0 Then MsgBox("Input Belum di isi", vbCritical, "Warning") Exit Sub End If s = txtInput.Text huruf(0) = Microsoft.VisualBasic.Left(s, 1) index(0) = 1 For i = 0 To n a = Microsoft.VisualBasic.Mid(s, i + 1, 1) b = Microsoft.VisualBasic.Mid(s, i + 2, 1) If a b Then k = k + 1 huruf(k) = b index(k) = 1 ElseIf a = b Then index(k) = index(k) + 1 End If Next d = k If k > 5 Then MsgBox("Jumlah variabel lebih dari 5", vbCritical, "Warning") Else For i = 0 To k var(i) = huruf(i) prb(i) = index(i) / n Next Dim frm As New frmHasil() frm.ShowDialog(frmHasil) End If End Sub Spoiler for coding form hasilnya: Dim cr As Double Dim n, x, k As Integer Dim s, a As String Private Sub btnBack_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnBack.Click Dim frm As New frmAwal() frm.ShowDialog(frmAwal) Me.Close() End Sub Private Sub btn_decode_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnBack.Click) Dim r, cr As Double Dim n As Integer Dim sa As String sa = "" If txtDecode.Text = "" Then MsgBox("Banyaknya decode belum di input", vbInformation, "Info") txtDecode.Focus() Exit Sub End If If txtInput.Text = "" Then MsgBox("Encoded Value Belum Di Input", vbInformation, "Info") txtInput.Focus() Exit Sub End If 'Pemindahan banyaknya decode n = Val(txtDecode.Text) If n = 0 Then 'Tidak ada yang di decode MsgBox("Tidak ada yang didecode", vbInformation, "Info") Exit Sub End If r = Val(txtInput.Text) For j = 0 To 5 If r >= LBound(j) And r < UBound(j) Then sa = sa & frmAwal.Text = var(j) lbl_output.Text = sa If Len(sa) = n Then Exit Sub End If cr = UBound(j) - LBound(j) r = (r - LBound(j)) / cr End If Next End Sub Private Sub btn_encode_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn_encode.Click If txtInput.Text = "" Then MsgBox("Input Masih Kosong", vbCritical, "Warning") txtInput.Focus() Exit Sub End If s = txtInput.Text n = Len(s) x = 0 'Fungsi Pengecekan a = Microsoft.VisualBasic.Left(s, 1) If a = var(0) Then x = 1 ElseIf a = var(1) Then x = 1 ElseIf a = var(2) Then x = 1 ElseIf a = var(3) Then x = 1 ElseIf a = var(4) Then x = 1 ElseIf x = 0 Then MsgBox("Input ada yang tidak sesuai dengan variabel", vbCritical, "Warning") Exit Sub Else For i = 0 To n x = 0 a = Microsoft.VisualBasic.Mid(s, i + 1, 1) If a = var(0) Then x = 1 ElseIf a = var(1) Then x = 1 ElseIf a = var(2) Then x = 1 ElseIf a = var(3) Then x = 1 ElseIf a = var(4) Then x = 1 ElseIf x = 0 Then MsgBox("Input ada yang tidak sesuai dengan variabel", vbCritical, "Warning") Exit Sub End If Next End If UBx = 1 LBx = 0 'Fungsi encode For i = 1 To n a = Microsoft.VisualBasic.Mid(s, i, 1) For j = 0 To 4 If a = var(j) Then cr = UBx - LBx UBx = LBx + (cr * UBound(j)) LBx = LBx + (cr * LBound(j)) End If Next Next lbl_output.Text = LBx & " - " & UBx End Sub Private Sub Form_Load() Dim rangea, rangeb As String For i = 0 To d - 1 txtVar(i).Visible = True mnu_probabilitas(i).Visible = True txtVar(i).Text = var(i) mnu_probabilitas(i).Text = prb(i) txt_range(i).Visible = True Next range1(0) = 0 range2(0) = prb(0) For i = 1 To d - 1 range1(i) = range2(i - 1) range2(i) = prb(i) + range1(i) Next For i = 0 To d - 1 rangea = Format(range1(i), "0.####") rangeb = Format(range2(i), "0.####") UBound(i) = range2(i) LBound(i) = range1(i) txt_range(i).Text = rangea & " - " & rangeb Next End Sub Private Sub txt_ndecode_Change() Dim x As String 'Pemerikasaan kondisi banyaknya encode x = txtDecode.Text Select Case x Case "0" To "5" 'Data Diterima Case "" 'Data diterima Case Else 'Data Ditolak MsgBox("Range karakter hanya 0-5", vbInformation, "Info") txtDecode.Text = "0" Exit Sub End Select End Sub nah kayanya di bag yg merah it ad problem..keluar warning "Class 'System.Windows.Forms.TextBox' cannot be indexed because it has no default property." dulu sempet cb d VB.6 n bisa di run..wktu it pas bwt txtboxnya udh otomatis ad indexnya..kl d VB.Net gmn y? mhon pncerahannya para sesepuh kaskus... ![]() ![]() nih screenshot formnya: Spoiler for form awal: ![]() Spoiler for form hasil: ![]() Terkait:
|
![]() |
|
|